BD6142AMUV
Datasheet
● Coil selection
The DC/DC is designed by more than 4.7μH. When L value sets to a lower value, it is possibility that the specific
sub-harmonic oscillation of current mode DC / DC will be happened. Please do not let L value to 3.3μH or below.
And, L value increases, the phase margin of DC / DC becomes to zero. Please enlarge the output capacitor value when you
increase L value. Please select lower DC resistance (DCR) type, efficiency still relies on the DCR of Inductor.
Please estimate Peak Current of Coil. Peak current can be calculated as following.
Peak Current calculation
<The estimate of the current value which need for the normal operation>
As over current detector of this IC is detected the peak current, it have to estimate peak current to flow to the coil by
operating condition.
In case of, - Supply voltage of coil = V In
- Inductance value of coil = L
- Switching frequency = fsw (Min=1.0MHz, Typ = 1.25MHz, Max = 1.5MHz)
- Output voltage = VOUT - Total LED current = I LED
- Average current of coil = Iave - Peak current of coil = Ipeak
- Cycle of Switching = T - Efficiency = eff (Please set up having margin)
- ON time of switching transistor = Ton - ON Duty = D
CCM: Ipeak = (V In / L) × (1 / fsw) × (1-( V In / VOUT)), DCM: Ipeak = (V In / L) × Ton
Iave=( VOUT × IOUT / V In ) / eff
Ton=(Iave × (1- V In / VOUT) × (1/fsw) × (L/ V In ) × 2) 1/2
Each current is calculated.
As peak current varies according to whether there is the direct current superposed, the next is decided.
CCM: (1- V In / VOUT) × (1/fsw) < Ton ? peak current = Ipeak /2 + Iave
DCM: (1- V In / VOUT) × (1/fsw) > Ton ? peak current = V In / L × Ton
(Example 1)
In case of, V In = 7.0V, L = 10μH, fsw = 1.2MHz, VOUT = 32V, I LED = 120mA, Efficiency = 88%
Iave = (32 × 120m / 7) / 88% = 0.62A
Ton = (0.62 × (1 - 7 / 32) × (1 / 1.2M) × (10μ / 7) × 2) 1/2 = 1.07μs
(1- V In / VOUT) × (1 / fsw) = 0.65μs < Ton(1.07μs) CCM
Ipeak = (7 / 10μ) × (1 / 1.2M) × (1 - (7 / 32)) = 0.46A
Peak current = 0.46A / 2 + 0.62A = 0.85A
(Example 2)
In case of, V In = 16.0V, L = 10μH, fsw = 1.2MHz, VOUT = 32V, I LED = 120mA, Efficiency = 88%
Iave = (32 × 120m / 16.0) / 88% = 0.27A
Ton = (0.27 × (1-16 / 32) × (1 / 1.2M) × (10μ / 16) × 2) 1/2 = 0.37μs
(1- V In / VOUT) × (1 / fsw)=0.41μs > Ton(0.37μs) DCM
Ipeak = V In / L x Ton = 16 / 10μ x 0.37μs = 0.59A
Peak current = 0.59A
*When too large current is set, output overshoot is caused, be careful enough because it is led to break down of the IC in
case of the worst.
DCM/CCM calculation
Discontinuous Condition Mode (DCM) and Continuous Condition Mode (CCM) are calculated as following.
CCM: L > VOUT × D × (1 - D) 2 × T / (2 × I LED )
DCM: L < VOUT × D × (1 - D) 2 × T / (2 × I LED )
*D = 1- V In / VOUT
(Example 1)
In case of, V In = 7.0V, L = 10μH, fsw = 1.2MHz, VOUT = 32V, I LED = 120mA
VOUT × D × (1 - D) 2 × T / (2 × I LED ) = 32 × (1 – 7 / 32) × (7 / 32) 2 × 1/(1.2 × 10 6 ) / (2 × 0.12) = 4.15μ < L(10μH)
? CCM
(Example 2)
In case of, V In = 12.0V, L = 10μH, fsw = 1.2MHz, VOUT = 32V, I LED = 60mA
VOUT × D × (1 - D) 2 × T / (2 × I LED ) = 32 × (1 – 12 / 32) × (12 / 32) 2 × 1/(1.2 × 10 6 ) / (2 × 0.06) = 19.5μ > L(10μH)
? DCM
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? 2011 ROHM Co., Ltd. All rights reserved.
TSZ22111 ? 15 ? 001
19/30
TSZ02201-0G3G0C400340-1-2
03.Dec.2012 Rev.001
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